<DocScrutinizer05>
that looks like a ferrite toroid, not a rod
<DocScrutinizer05>
meh! sb0, yes it might work, but definitely not nicely
<DocScrutinizer05>
but I think they messed up orientation of primary and secondary coil of transformer
<sb0>
oh yes sure, it's not nice. but does it oscillate at all and drive the transformer?
<sb0>
the secondary circuit is driving the transistor between collector and base, not between the emitter and base as one would expect
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<DocScrutinizer05>
yeah, it looks pretty strange
<DocScrutinizer05>
then OTOH B-W vs B-C doesn't _really_ make a difference for AC, only for DC
<DocScrutinizer05>
s/B-W/B-E/
<qi-bot>
DocScrutinizer05 meant: "then OTOH B-E vs B-C doesn't _really_ make a difference for AC, only for DC"
<DocScrutinizer05>
with the coil between B-E you had no bias opening the transistor, and you'd need an additional resistor to create such bias to make the circuit start up
<DocScrutinizer05>
anyway it's a really nasty circuit, that could easily latch up
<DocScrutinizer05>
the components "Light" and "B"(attery) are not really defined and probably complex, with their complexity being relevant in that nasty circuit
<DocScrutinizer05>
maybe the whole circuit is actually only working by operating the transistor in a possibly destructive way.
<DocScrutinizer05>
but *maybe* those schematics are outright wrong
<DocScrutinizer05>
I mean, you can't drain current from a NPN base, you only can dump current into it
<DocScrutinizer05>
the "Light" component actually looks like it might be an LED energy-saver lamp, which means it is a Graetz-bridge with a buffer capacitor behind
<DocScrutinizer05>
this would massively change the way this circuit works
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<sb0>
whitequark, not exactly, the output is in series with the base
<whitequark>
ah, hm
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<DocScrutinizer05>
yeag, it's terribly weird
<DocScrutinizer05>
yeah, even
<DocScrutinizer05>
it has one obvious advantage (if you can call advantages on a defunct design): switching off the load ('Lamp') will immanently switch off the circuit
<DocScrutinizer05>
a joule-thief works via the positive feedback (like basically all oscillators do), so opening the C-E of transistor must make current flow through 'lamp', until transistor eventually switches off (for whatever reason, prolly saturation of the transformer) and then the feedback will need to apply *low* voltage to transistor to make a positive feedback... :-o where does the stored energy in transformer get dissipated then??!, *at
<DocScrutinizer05>
least* this circuit needs a clamp diode E-B to allow transformer energy to power the 'lamp' while current flows from B through coil to 'lamp' and then to don't know where (mind you C-E closed)