<tsuyoshi>
uhh. I guess I'm about to use it commercially
<tsuyoshi>
as soon as I finish the program I'm working on, anyway
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<twobitsprite>
does someone know where I can find a vim mode for ocamlyacc? the vim scripts search is down
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<flux__>
hmh.. ocamldebug is quite difficult to use without emacs.. and apparently it's broken for xemacs. nice :)
<flux__>
is there a standalone gui for it? or only with cameleon?
<flux__>
maybe I'll just give at try to cameleon
<flux__>
..which is not quite apparent, atleast not in debian
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<flux__>
IMHO the usability of ocamldebug is far, far away from, say, gdb :-)
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<Eridius>
so I'm going through ocaml-tutorial.org, and it seems to not want to explain why a bunch of example functions take a single unit argument
<Mr_Awesome>
which functions?
<malc_>
Eridius: because they are executed for a side effect and return non meaningful value, hence they return () - unit
<malc_>
oh taking a signle
<malc_>
same reason really
<Mr_Awesome>
they dont necessarily return a non-meaningful value, and they are always executed for a side effect per se
<Mr_Awesome>
they might be used to retrieve data about the state of something
<Eridius>
it explains it in the case of optional arguments, but a lot of the example functions have no optional arguments
<Eridius>
best thing I can come up with is simply convention because of the optional argument thing, so you get used to ending function argument lists in ()
<Eridius>
for example, whenever an example function uses a nested loop function, the loop function is always declared as taking a ()
<malc_>
let's put it this way.. `let a = ref 0; let get_a () = !a;'
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<Eridius>
ahh, without the () it evaluates the expression immediately
<Eridius>
the way the tutorial explained it, it seemed like without the () it still bound get_a to the expression !a and not the result of evaluating it
<malc_>
get will be 0-ary function (i.e. a pure value) other it's ordinary function which dereferences a and returns this value as a result